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Last Checked Feb. 5, 2023

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Sat Jan 14 21:43:56 +0000 2023

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Nassim Nicholas Taleb @nntaleb

@jonathan26673 @michal_chren For n large, 0<x<1,log(1+x+x^n]->log[1+x]. So integrate Log[1+x], which =-x + Log[1 + x] + x Log[1 + x]|_0^1 = 2 log[2]-1 — PolitiTweet.org

Posted Jan. 14, 2023