Nassim Nicholas Taleb

@nntaleb ↗

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Last Checked May 20, 2022

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Fri May 20 09:36:13 +0000 2022

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Nassim Nicholas Taleb @nntaleb

@arthurzqx Lhs is pi/2 regardless of T, no? — PolitiTweet.org

Posted May 20, 2022 Deleted after an hour

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Nassim Nicholas Taleb @nntaleb

2) The identity as presented above is wrong. Take f[x]= Sin[x], lhs the (standard) integral of Sinc=pi/2. Rhs only = pi/2 for T -> \infty. Perhaps they mean that there exists an odd function with period T for which the identity holds, where f is a sum. — PolitiTweet.org

Posted May 20, 2022 Deleted after 3 hours

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Nassim Nicholas Taleb @nntaleb

@arthurzqx Yes thanks... to be compatible with the denominator with tan. — PolitiTweet.org

Posted May 20, 2022