
Nassim Nicholas Taleb @nntaleb
No, it is not (1.01)^365 since I used Log[deaths date t]-Log[deaths date t-1] so my growth rate is the exponential one. Hece Exp[365/100]. Look at code above. — PolitiTweet.org
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Tue Jun 30 18:34:09 +0000 2020
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Likely AvailableNassim Nicholas Taleb @nntaleb
No, it is not (1.01)^365 since I used Log[deaths date t]-Log[deaths date t-1] so my growth rate is the exponential one. Hece Exp[365/100]. Look at code above. — PolitiTweet.org