Nassim Nicholas Taleb @nntaleb
@LesVINCENTs @SrinivasR1729 Somehow because the negative log = log[abs[]]+ i \pi is not really a function, when you solve as 1 rather than 2 integrals you get a residual of \frac{\pi^3}{3}. Otherwise the left integral is something like -4/5 zeta(3) offset by the second integral. — PolitiTweet.org
