Richard Spencer @RichardBSpencer
Bear with me on this one... Let’s imagine that there are four basketball players that make free throws at 92%. If each shoots one shot, what is the probability that at least one will miss? P (one miss in 4 shots) = 1 — P (success rate) P = 1 — .92^4 P = .28 or 28% — PolitiTweet.org